1樓：匿名使用者
x^2-y^2/x^2-(y-z)^2/x^2+2xy+y^2/(x-y)^2-x^2*x62+xy-xz/x^2-xy
=（x+y)(x-y)/)x-y+z)(x+y-z)]*[(x-y+z)(x-y-z)/(x+y)^2]*[x(x+y-z)/x(x-y)]
=(x-y-z)/(x+y)
2樓：匿名使用者
原始數字=(x+y)*(x-y)*(x-y+z)*(x-y-z)*x*(x+y-z)/<(x+y-z)*(x-y+z)*(x+y)^2*x(x-y)>
=(x+y-z)/(x+y)
3樓：0皮o皮
用畫圖寫的，希望能看得清
4樓：匿名使用者
(x²-y²)/[x²-(y-z)²]÷(x²+2xy+y²)/[(x-y)²-z²]×(x²+xy-xz)/(x²-xy)
=(x-y)(x+y)/(x-y+z)(x+y-z)×(x-y+z)(x-y-z)/(x+y)²*x(x+y-z)/x(x-y)
=(x-y)(x+y)(x-y+z)(x-y-z)*(x+y-z)/[(x-y+z)(x+y-z)(x+y)²(x-y)]
=(x-y-z)/(x+y)
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